Answer:
![log_{10} (100) = 2](https://tex.z-dn.net/?f=log_%7B10%7D%20%20%28100%29%20%3D%202)
Step-by-step explanation:
Here, the given expression is:
![log_{10} (y) = 2](https://tex.z-dn.net/?f=log_%7B10%7D%20%20%28y%29%20%3D%202)
Now, by logarithm rules, we know
if ![log_{b}(x) = z](https://tex.z-dn.net/?f=log_%7Bb%7D%28x%29%20%3D%20z)
, then x =![b^{z}](https://tex.z-dn.net/?f=b%5E%7Bz%7D)
Comparing here, b = 10 and z = 2
⇒ y = ![10^{2} = 100](https://tex.z-dn.net/?f=10%5E%7B2%7D%20%20%3D%20100)
or, ![log_{10} (100) = 2](https://tex.z-dn.net/?f=log_%7B10%7D%20%20%28100%29%20%3D%202)
<span>Together they wrap 14+12 = 26 boxes per hour.
t hours × 26 boxes/hour = 65 boxes
C</span><span>
</span>
Answer:
C is correct
Step-by-step explanation:
Given: System of linear inequality
![y](https://tex.z-dn.net/?f=y%3C-%5Cdfrac%7B1%7D%7B2%7Dx)
![y\geq 2x+3](https://tex.z-dn.net/?f=y%5Cgeq%202x%2B3)
First we will draw the graph of system of equation and then see the correct option.
Equation 1: ![y](https://tex.z-dn.net/?f=y%3C-%5Cdfrac%7B1%7D%7B2%7Dx)
We will make the table.
x : -2 0 2
y : 1 0 -1
Test Point: (0,4)
0<-2 ( False )
Shaded area away from (0,4)
Equation 2:![y\geq 2x+3](https://tex.z-dn.net/?f=y%5Cgeq%202x%2B3)
We will make the table.
x : -2 0 2
y : -1 3 7
Test Point: (0,4)
4≥3 ( True )
Shaded area towards (0,4)
Please see attachment for graph.
Hence, C is common shaded area (region)