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tekilochka [14]
3 years ago
9

The price of a 5 minute phone call is $1.25 what is the price of a 17 minute phone call?

Mathematics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

The price of 17 minutes call = $4.25

Step-by-step explanation:

Given

  • Minutes spent = 5 minutes
  • Cost of 5 minute call = $1.25

Thus,

The unit rate can be calculated

Unit rate = $1.25 / 5 minutes

Unit rate  = $0.25 per minute

So,

The price of one minute call = $0.25

The price of 17 minutes call = 0.25 × 17

                                               = $4.25

Therefore, the price of 17 minutes call = $4.25

pychu [463]3 years ago
3 0

Answer:

$4.25

Step-by-step explanation:

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The perimeter of a rectangle is 20 inches.The length is 2 inches less than twice the width.
SSSSS [86.1K]

Answer:

width = 6

length = 4

Step-by-step explanation:

perimeter = 2L + 2W

L = W - 2

plug in perimeter:

20 = 2L + 2W

you know the length is 2 less than the width

plug in (w - 2) for L:

20 = 2(w - 2) + 2w

solve for w:

20 = 2w - 4 + 2w

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6 0
3 years ago
The number of bank robberies that occur in Lagos is modeled to be Poisson distributed with mean of 1.8 per day. Find the probabi
cupoosta [38]

The Poisson distribution is a discrete distribution that calculates the likelihood that a certain number of events will occur within a certain amount of time.

The probability of getting exactly three robberies in a day is 0.1607.

<h3>What is meant by poison distribution?</h3>

The Poisson distribution is a discrete probability distribution used in probability theory and statistics to express the likelihood that a given number of events will occur within a specified time or space interval if they occur at a known constant mean rate and regardless of the interval since the last event.

The Poisson distribution is a discrete distribution that calculates the likelihood that a certain number of events will occur within a certain amount of time.

In the poison distribution a discrete random variable X has the following probability mass function,

$P(X=x)=\frac{e^{-\lambda} \cdot \lambda^x}{x !}$, where $\lambda$ is the mean of the distribution and $x=0,1,2,3 \ldots \ldots$

Given that $\lambda=1.8$

The required probability, $P(X=3)=\frac{e^{-1.8} .(1.8)^3}{3 !}=0.1607$

Therefore, the probability of getting exactly three robberies in a day is = 0.1607.

To learn more about poison distribution refer to:

brainly.com/question/9123296

#SPJ9

6 0
1 year ago
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