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tekilochka [14]
3 years ago
9

The price of a 5 minute phone call is $1.25 what is the price of a 17 minute phone call?

Mathematics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

The price of 17 minutes call = $4.25

Step-by-step explanation:

Given

  • Minutes spent = 5 minutes
  • Cost of 5 minute call = $1.25

Thus,

The unit rate can be calculated

Unit rate = $1.25 / 5 minutes

Unit rate  = $0.25 per minute

So,

The price of one minute call = $0.25

The price of 17 minutes call = 0.25 × 17

                                               = $4.25

Therefore, the price of 17 minutes call = $4.25

pychu [463]3 years ago
3 0

Answer:

$4.25

Step-by-step explanation:

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three bottles of water can hold three glass of water

Step-by-step explanation:

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the volume of hemisphere is 1527.4cm^3.find the radius of the hemisphere to the nearest whole whole number.(take π to be 22/7)​
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Answer:

radius of the hemisphere = 9 cm approx

Step-by-step explanation:

Volume of hemisphere = \frac{2}{3} \pi r^{3}

1527.4 = \frac{2}{3} * \frac{22}{7} * r^{3}

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The U.S. Department of Transportation provides the number of miles that residents of the75 largest metropolitan areas travel per
Leya [2.2K]

Answer:

a. The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88

b. The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

Step-by-step explanation:

a. According to the given data we have the following:

Buffalo residents mean=22.5

Standard deviation=8.4

n=50

Boston residents mean=18.6

Standard deviation=7.4

n=40

Hence, the point estimate is the difference of the means=22.5-18.6=3.9

The standard error=√((s1∧2/n1)+((s2∧2/n2))=√((8.4∧2/50)+(7.4∧2/40))=1.67

Therefore, the difference of miles=n1+n2-2=50+40-2=88

The point estimate of the difference between the mean number of miles that Buffalo residents travel per day and the mean number of miles that Boston residentstravel per day is 88.

b. The critical value of t at 95% confidence level and DoF=88 is 1.987

The interval:(x1-x2)+ (critical value* std error)

=3.9-(1.987*1.67),3.9+(1.987*1.67)

Difference between mean=(0.58171,7.21829)

The 95% confidence interval for the difference between the two population means is (0.58171,7.21829)

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