Answer:

Step-by-step explanation:
Use the volume of cube formula.


![\displaystyle\sqrt[3]{5.832} =s](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B3%5D%7B5.832%7D%20%3Ds)

Answer:
$14722.14
Step-by-step explanation:
We are given that
In 2015
The value of jewel=$17500
Rate of appreciation, r=2.5%
We have to find the initial value of the jewel when it was first bought.
Time, n=7 years
Final value=
Using the formula



Initial value=$14722.14
Hence, the the initial value of the jewel when it was first bought=$14722.14
9.5 or 9 1/2 if you want them both to be an equal mix
First you have to find the like terms
3xy + 10xy - 2xy and -5x + 2x
After that you solve for the like terms to find the final answer
11xy-3x
Answer:

Step-by-step explanation:
Matrix Equations
Given:


Find X such that:
B - X = 3A
Subtracting B:
- X = 3A - B
Multiplying by -1:
X = -3A + B
Find -3A:

Add to B:

Thus:
