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Sliva [168]
3 years ago
6

How do you solve x3 (y-5) (x-8) (the numbers next to the variables (letters) are supposed to be exponents)

Mathematics
1 answer:
Galina-37 [17]3 years ago
7 0
Y^-5
x^-5
because you have to put together all the x and then put all the y's together
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Find the midpoint of NP⎯⎯⎯⎯⎯ given N(2a, 2b) and P(2a, 0).
geniusboy [140]

Answer:

(2a, b )

Step-by-step explanation:

Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{1}{2}(x₁ + x₂ ), \frac{1}{2}(y₁ + y₂ ) ]

Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus

midpoint = [ \frac{1}{2}(2a + 2a), \frac{1}{2}(2b + 0 ) ] = (2a, b )

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Question 14 of 16
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sertanlavr [38]
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I NEED HELP ASAP<br> Write the equation of the line in fully simplified slope-intercept form.
Agata [3.3K]

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Step-by-step explanation:

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Solve for x and y <br> 8x-2y=24
TiliK225 [7]

Answer: For y it's y=4x−12 and for x it's x=12+y/4

Step-by-step explanation:

SOLVING FOR X

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

4x=12+y

x=12+y/4

SOLVING FOR Y

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

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y=−12+4x

y=4x−12

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)

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