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vitfil [10]
3 years ago
11

sylvia is saving up to buy a new phone. so far she has saved $45. she needs at least $360 to buy the phone and some accessories.

she wants to buy the phone in 15 weeks write an inequality to how much money sylvia must save each week.
Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0

Answer: she need 315 more to buy the phone hope this helps

Step-by-step explanation:

Luda [366]3 years ago
6 0
Sylvia needs $315 more to buy a phone and some accessories. She has 15 weeks to split this up. To find out how much she should save each week, we can do 315/15 which is 21. Sylvia needs to save $21 per week.
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A simple modeling clay recipe
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3 0
2 years ago
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Find the Least Common Multiple of these two monomials:
bonufazy [111]

LCM 14 & 24 = 168

then use the highest exponents for the variables

 answer = 168x^6y^6z^8

7 0
3 years ago
46+ 2/7w<br> w= -1/2<br> You don't need to show your work
Tomtit [17]
46.1428 or -46(3/14)
3 0
3 years ago
Slices of pizza for a certain brand of pizza have a mass that is approximately normally distributed with a mean of 67.7 grams an
Alexxx [7]

Answer:

<u>a. s.e. = 0.338</u>

<u>b. The  probability of finding a random slice of pizza with a mass of less than 67.2 grams is 0.5871 or 58.71%</u>

<u>c. The probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams is 0.0694 or 6.94%</u>

d. <u>The sample mean of 62.75 would represent the 15th percentile</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question properly:

μ of the mass of slices of pizza for a certain brand = 67.7 grams

σ of the mass of slices of pizza for a certain brand = 2.28 grams

2. For samples of size 20 pizza slices, what is the standard deviation for the sampling distribution of the sample mean?

Let's recall that the standard deviation of the sampling distribution of the mean is called the standard error of the mean and its formula is:

μσs.e.= √σ/n, where n is the sample size.

s.e. = √2.28/20

<u>s.e. = 0.338</u>

3. What is the probability of finding a random slice of pizza with a mass of less than 67.2 grams?

Let's find the z-score for X = 67.2, this way:

z-score = (X - μ)/σ

z-score = (67.2 - 67.7)/2.28

z-score = 0.5/2.28

z-score = 0.22 (rounding to the next hundredth)

Now, using the z-table, let's find p, the probability:

p (z = 0.22) = 0.5871

<u>The  probability of finding a random slice of pizza with a mass of less than 67.2 grams is 58.71%</u>

4.  What is the probability of finding a 20 random slices of pizza with a mean mass of less than 67.2 grams?

Let's use the central limit theorem to find the z-score, this way:

z-score = X - μ/s.e

z-score = 67.2 - 67.7/0.338

z-score = -0.5/0.338

z-score = - 1.48

Now, using the z-table, let's find p, the probability:

<u>p (z = -1.48) = 0.0694</u>

5. What sample mean (for a sample of size 20) would represent the bottom 15% (the 15th percentile)?

For p = 0.150, let's find the z-score:

z-score = - 2.17

z-score = X - μ/s.e

- 2.17 = (X - 67.7)/2.28

- 4.95 = X - 67.7

X = 67.7 - 4.95

X = 62.75 (rounding to the next hundredth)

<u>The sample mean of 62.75 would represent the 15th percentile</u>

7 0
3 years ago
HELP PLEASE TELL ME WHICH ONE WITH AN EXPLAINATION
Alex787 [66]

Answer:

Im not sure, but i think it's the bottom because there not working with negatives

Step-by-step explanation:

Don't put that as the answer tho, im not too sure.

6 0
3 years ago
Read 2 more answers
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