Answer:
A. E(x) = 1/n×n(n+1)/2
B. E(x²) = 1/n
Step-by-step explanation:
The n candidates for a job have been ranked 1,2,3....n. Let x be the rank of a randomly selected candidate. Therefore, the PMF of X is given as
P(x) = {1/n, x = 1,2...n}
Therefore,
Expectation of X
E(x) = summation {xP(×)}
= summation {X×1/n}
= 1/n summation{x}
= 1/n×n(n+1)/2
= n+1/2
Thus, E(x) = 1/n×n(n+1)/2
Value of E(x²)
E(x²) = summation {x²P(×)}
= summation{x²×1/n}
= 1/n
You would use the counting principal. 12X3X3
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Answer:
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Given:
Find:
Solution: In order to simplify the inequality we can simply add 4 to both sides which would isolate x.
<u>Add 4 to both sides</u>
Therefore, an inequality that would be equivalent to the one that was provided in the problem statement is x < 13.
Answer:
D. x = 9
Step-by-step explanation:
6 x 3/2 = 9