Chemical reaction hope this helped :)))
<span>B.) Information on the distance from the ocean to the rivers that the salmon use. >? i think this would be it since they would not even be able to reach the area needed to breed >?</span>
Answer:
hypha
mycelium
fruiting body
spores
Explanation:
<em>A typical fungi thallus includes many filamentous hypha that combine to form mycelium that grows underground, and produce a fruiting body reproductive structure that produce spores that disperse on the wind to new habitat.</em>
Fungi body are generally made up of hypha, a network of which forms the mycelium. The mycelium grows underground within the substrate and occasionally bring out fruiting bodies which bear the sporangium containing the spores. The spores act as agent of dispersal and are used to form new organisms when the conditions are right.
Answer: The frequency of brown beetles is 0.32.
Explanation: The frequency of A1 allele is 0.8. As p+q=1, or the sum of dominant and recessive frequencies equals 1 or 100%:
1 - 0.8 = 0.2
In Hardy-Weinberg principle,
2pq represents the frequency of heterozygote individuals, so:
genotype A1A2 = 2*0.8*0.2 = 0.32.
Thus, the frequency of brown beetles (A1A2) in the population is 0.32.
Answer:
Man's genotype: XᴮY
Woman's genotype: XᴮXᵇ
Daughter's genotype: XᵇXᵇ
The daughter is not the man's child.
Explanation:
Color blindness is a sex-linked trait caused by a recessive allele located in the X chromosome (Xᴮ=normal vision; Xᵇ-color blind).
Women have two X chromosomes, while men have an X and a Y chromosomes. For that reason, women need to have two recessive alleles to be color blind, while men only need one Xᵇ to be colorblind.
Since the man has normal color vision, his genotype would be XᴮY.
If the daughter is her father's, she would have inherited his dominant Xᴮ allele, so she would have normal vision. However, she is colorblind, so her genotype is XᵇXᵇ. She is not the man's daughter.
The mother also has normal color vision, but her daughter inherited a recessive allele from her, so her genotype is heterozygous XᴮXᵇ.
