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3 years ago

NEED ANSWER ASAP GIVING LOTS OF BRAINLIST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Lerok [7]3 years ago

6 0

1. X2 +3x+5

2. 5x-1+

3. x2+ 3x-5

BlackZzzverrR [31]3 years ago

6 0

Answer:

this is your answer of first one..

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Please help on this i cant understand it

poizon [28]

Answer:

to get the probability you add the number of figure all together

divide the number of spheres with the total

2 ÷ 10

you get 1÷ 5

you get the answer as 0.2

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3 years ago

A television Mark 1600 was sold for 1200 what percent discount was given on that television

adoni [48]

Answer:

25%

Step-by-step explanation:

Discount = 1600 - 1200 = 400

Percentage discount

$= \frac{400}{1600} \times 100 \\ \\ = \frac{400}{16} \\ \\ = 25\%$

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3 years ago

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denis-greek [22]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Fill in the blank with the correct inequality symbol

12345 [234]

Answer:

Step-by-step explanation:

4 is greater than 3

sqrt15 is greater than sqrt6

So 4+sqrt15 must be greater than 3+sqrt6

6 0

3 years ago

Let the probability of success on a Bernoulli trial be 0.26. a. In five Bernoulli trials, what is the probability that there wil

andreyandreev [35.5K]

Answer:

0.3898 = 38.98% probability that there will be 4 failures

Step-by-step explanation:

A sequence of Bernoulli trials forms the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Let the probability of success on a Bernoulli trial be 0.26.

This means that $p = 0.26$

a. In five Bernoulli trials, what is the probability that there will be 4 failures?

Five trials means that $n = 5$

4 failures, so 1 success, and we have to find P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.26)^{1}.(0.74)^{4} = 0.3898$

0.3898 = 38.98% probability that there will be 4 failures

4 0

3 years ago