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denis-greek [22]
3 years ago
12

If all the trees in a forested area are cut down, in what two ways will the air

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

Option B and Option C

Step-by-step explanation:

If all trees in a forested area are cut down, in the following ways the air composition will change in that area:

Carbon dioxide levels increase

Oxygen levels decrease

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Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
What is the least common multiple of 9 and 8
leonid [27]

Answer:

72 is the least common multiple

6 0
3 years ago
Read 2 more answers
You write down the temperatures at different times on one of the match days. Time Temperature Midnight -6°C 4 am -8°C 8 am -4°C
fenix001 [56]
The highest is 7 degrees and lowest is -8 so subtract and you get a difference of 15 degrees
5 0
3 years ago
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1. A group of workers is harvesting berries at a constant rate. An equation that represents the number of baskets of berries the
lbvjy [14]

Answer: (a) The slope of the line is 5 and the y-intercept is (0,10). (b) The rate of change is 5 and the initial amount is 10.

Explanation:

The given equation is,

y=5x+10     .... (1)

(a)

The slope intercept form of the a line is,

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Where, m is slope and (0,b) is y-intercept.

On comparing (1) and (2) we get,

m=5, b=10

Therefore, the slope is 5 and the y-intercept is (0,10).

(b)

The rate of change is also known as slope therefore the rate of change is 5.

To find the initial amount put x=0 in the given equation.

y=5(0)+10=10

Therefore, the initial value is 10.

The rate of change represents the number of baskets of berries the workers picked increased by 5 units per unit of time.

The initial amount shows the number of  baskets of berries the workers picked before the workers starts harvesting.

(c)The graph is shown below.

Since x represents the time in hours, therefore x is always greater that or equal to 0.

7 0
3 years ago
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Silcon-28 has a mass-per-nucleon of 1.003 amu. Iron-56 has a mass-per-nucleon of 0.99723 amu. Cadmium-112 has a mass-per-nucleon
Ber [7]

Answer:

no

Step-by-step explanation:

4 0
3 years ago
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