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Ad libitum [116K]
3 years ago
9

What is the approximate area of a sector given O= 56 degrees with a diameter of 12m?​

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Area of sector is 17.584 meters

<em><u>Solution:</u></em>

Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m

Diameter = 12 m

Radius = Diameter / 2 = 6 m

An angle of  56 degrees is the fraction \frac{56}{360} of the whole rotation

A sector of a circle with a sector angle of 56 degrees is therefore also the fraction \frac{56}{360} of the circle

The area of the sector will therefore also be  \frac{56}{360} of the area

\text{ sector area } = \frac{56}{360} \times \pi r^2\\\\\text{ sector area } = \frac{56}{360} \times 3.14 \times 6^2\\\\\text{ sector area } = 17.584

Thus area of sector is 17.584 meters

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A general line in the slope-intercept form is written as:

y = m*x + b

Where m is the slope and b is the y-intercept.

Two linear equations are perpendicular if the product between the two slopes is equal to -1.

Rewriting the given line we can get:

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y = 21/3 - x/3

y = (-1/3)*x + 21/3

Then the slope is (-1/3), if our line is perpendicular to this one, then:

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our line is:

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To find the value of b, we use the fact that our line passes through (1, - 3)

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Learn more about linear equations:

brainly.com/question/1884491

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1 year ago
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I believe that it would be A+C+S but is there more to the question?

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