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Salsk061 [2.6K]

2 years ago

12

A photograph measures 12 centimetres by 20 centimetres. A printing company enlarges the photo. The length of the enlarged photo

is 60 centimetres. What could he other dimension of the enlarged photo be?

1 answer:

Studentka2010 [4]2 years ago

6 0

Answer:

36 centimeters

Step-by-step explanation:

Since one side is 60 centimeters, just divide by 20 and get 3

Then multiply 12 by 3 and get 36

I hope this helps!

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23.0833333333 in fraction form

Black_prince [1.1K]

Answer:

230833333333/10000000000

Step-by-step explanation:

Well to write this as a fraction you will first write 23.0833333333 as our numerator

Now you would multiply numerator by denominator which you could put 1 as denominator and multiply by 10 and you get your whole number/your answer.

Hope this helps have a great day:)

4 0

1 year ago

50× 3/8 how to reduce answer to lowest te

hoa [83]

The lowest term is $\frac{75}{4}$ .

Solution:

Given expression is $50\times\frac{3}{8}$

<u>To reduce this term to the lowest term:</u>

$$50\times\frac{3}{8}=\frac{50}{1}\times\frac{3}{8}$

Multiply the numerator and denominator.

$$50\times\frac{3}{8}=\frac{150}{8}$

Now, divide the numerator and denominator by the greatest common factor.

Here 150 and 8 both have common factor 2.

So, divide numerator and denominator by 2.

$$=\frac{150\div2}{8\div2}$

$$=\frac{75}{4}$

$$50\times\frac{3}{8}=\frac{75}{4}$

Hence the lowest term is $\frac{75}{4}$ .

4 0

2 years ago

5 plus 2 minus 6 times 4

nevsk [136]

Answer:

714

Step-by-step explanation:

5+2=7

7-6=1

1x4=4

3 0

2 years ago

Read 2 more answers

Can someone please help me with this? I don’t understand what is given.

a_sh-v [17]

$\bf BC=2BA\\ BE = 2BD \end{cases} \cfrac{BC}{BE}=\cfrac{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BA}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~BD}\implies \cfrac{BC}{BE}=\cfrac{BA}{BD}\impliedby \begin{array}{llll} \textit{equal ratio of sides}\\ \textit{similar triangles} \end{array}$

8 0

3 years ago

Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.

kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = $\frac{38}{60} = 0.634$

Therefore, the probability is given by:

$P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]$

P $(p\leq 0.634) = P[z\leq -1.87188]$

P $(p\leq 0.634) = P[z\leq -1.87] = 0.0298$

Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0

2 years ago