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Temka [501]
3 years ago
11

The length of s is 2/3 the length of t. If s has an area of 368 cm squared find the perimeter of the figure

Mathematics
2 answers:
mezya [45]3 years ago
8 0
The correct answer is 78.2 hope this helped 
ser-zykov [4K]3 years ago
3 0
s = \frac{2}{3}t
\\\ \frac{2}{3}t*t = \frac{2}{3}t^2
\\\ \frac{2}{3}t^2 = 368
\\\ t^2 = \frac {3}{2}368
\\\ t^2 = 552
\\\ t \approx 23.5
\\\ s \approx 15.6
\\\ P \approx 78.2
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a system of equations is graphed here. which system of equations does the graph represent? A) y = 3x + 2y = -2x + 5 B) y = 3x -
n200080 [17]

Notice that the line with negative slope has a y-intercept of 5 and the line with positive slope has a y-intercept of 2.

On the other hand, the slope of the line with negative slope is -2, while the slope of the line with positive slope is 3 (This can be identified since in one case, the value of y decreases by 2 for each increase of 1 unit in x, and in the other, the value of y increases by 3 for each increase of 1 unit in x).

Using the y-intercept form to represent each line, the system of equations represented by the graph must be equivalent to:

\begin{gathered} y=-2x+5 \\ y=3x+2 \end{gathered}

From the given options, the one that displays the correct system of equations is option A.

Therefore, the answer is:

\begin{gathered} A) \\ y=3x+2 \\ y=-2x+5 \end{gathered}

6 0
1 year ago
If f(x) = - 3x - 3. g(x) = 2x2 + 6x - 5. and h(x) = - 8x2 + 6. find f(-3). I REALLY NEED THIS ​
shepuryov [24]

Answer:

f(-3) = 6

Step-by-step explanation:

input -3 in f(x)

so f(-3) = -3(-3) - 3

multiple and add

f(-3) = 6

5 0
4 years ago
Can someone solve this for me?
Helga [31]

well, we know it's a rectangle, so that means the sides JK = IL and JI = KL, so

\stackrel{JK}{3x+21}~~ = ~~\stackrel{IL}{6y}\implies 3(x+7)=6y\implies x+7=\cfrac{6y}{3} \\\\\\ x+7=2y\implies \boxed{x=2y-7} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{JI}{6y-6}~~ = ~~\stackrel{KL}{2x+20}\implies 6(y-1)=2(x+10)\implies \cfrac{6(y-1)}{2}=x+10 \\\\\\ 3(y-1)=x+10\implies 3y-3=x+10\implies \stackrel{\textit{substituting from the 1st equation}}{3y-3=(2y-7)+10} \\\\\\ 3y-3=2y+3\implies y-3=3\implies \blacksquare~~ y=6 ~~\blacksquare ~\hfill \blacksquare~~ \stackrel{2(6)~~ - ~~7}{x=5} ~~\blacksquare

5 0
2 years ago
What is the answer to (6+4)tothe3power-1tothe8power
Ipatiy [6.2K]

Hey there!

\huge\boxed{(6 + 4)^3 - 1^8}

\huge\boxed{= 10^3 - 1^8}

\huge\boxed{10^3}

\huge\boxed{= 10\times10\times10}

\huge\boxed{= 100\times10 }

\huge\boxed{= 1,000}

\huge\boxed{1^{8}}

\huge\boxed{= 1\times1\times1 \times 1 \times 1 \times 1 \times 1 \times 1}

\huge\boxed{= 1 \times 1 \times 1 \times 1}

\huge\boxed{= 1\times1}

\huge\boxed{= 1}

\huge\boxed{1,000 - 1}

\huge\boxed{= 999}

\huge\text{Answer: \textsf{999}}

\huge\text{Good luck on your assignment \& enjoy your day!}

~\huge\boxed{\frak{Amphitrite1040:)}}

8 0
3 years ago
Which expression is equivalent to (4g3h2k4)3
RSB [31]

Answer:

d) 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

      \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}    = 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

           =     \frac{(4g^{3} h^{2}k^{4} )^{3}  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

By using

        (ab)ⁿ = aⁿbⁿ

         \frac{a^{m} }{a^{n} } = a^{m-n}

   =     \frac{(4)^{3} g^{9} h^{6}k^{12} )  }{8g^{3}h^{2}  } - (h^{5} k^{3} )^{5}

After simplification , we get

  = 8g^{9}g^{-3} h^{6} h^{-2} k^{12}  - (h^{5} k^{3} )^{5}

 = 8g^{9-3}h^{6-2}  k^{12}  - (h^{5} k^{3} )^{5}

= 8g^{6}h^{4}  k^{12}  - (h^{25} k^{15} )

3 0
3 years ago
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