Answer:
The three given points are the vertices of a right triangle.
Step-by-step explanation:
Answer:
c) 1 2 4 8
Step-by-step explanation:
<u>Explanation </u>:-
<u><em>Geometric sequence</em></u>
The sequence is of the form a , a r , a r² , a r³ ,.......
'a' is the first term
'r' is the common ratio
1 , 1(2) , 1( 2)² , 1( 2 )³ ...... is a geometric sequence
here a = 1
common ratio 


<em>The sequence 1 2 4 8 is a geometric sequence</em>

Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
Is it x = 85
196 +2x+(3x-6)
subtract 196 on both sides
simplify
add 6 on both sides
divide by 2