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Afina-wow [57]
3 years ago
10

The circumference of a circle is 11pie inches. What is the area, in square inches, of the circle?express answer in terms of pie

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0
Here is ur ans
hope this is helpful

Rufina [12.5K]3 years ago
5 0
Answer is 94.985.

I have a simple way to remember PI. Here have a go for yourself
"PI  R squared sounds like AREA to me, if I need a circumfrence I'll just use PI D"
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What is the least common multiple of 26 and 39?
GuDViN [60]

Answer:

78

Step-by-step explanation:

Find the prime factorizations of the two numbers:

26 = 2 * 13

39 = 3 * 13

The LCM is the product of common and not common factors with the higher exponent.

LCM = 2 * 3 * 13 = 78

Answer: 78

5 0
3 years ago
What are the answers to 2 and 4
podryga [215]
The answer to 2 is 14 and the answer to 4 is b
7 0
3 years ago
Find the value of k<br> 4x+y=8<br> y=kx+2<br><br> options<br><br> -4<br> 4<br> -1/4<br> 1/4
nexus9112 [7]

Answer:

4 i think im not sure

Step-by-step explanation:

Subtract yy from both sides of the equation.

4x=8−y4x=8-y

y=kx+2y=kx+2

Divide each term by 44 and simplify.

Tap for more steps...

x=2−y4x=2-y4

y=kx+2

6 0
2 years ago
A company is expanding its building area from 14,000 square feet to 17,640 square feet. What is the percentage increase of the a
natali 33 [55]

Answer:

its about 7.9% I think .... ............

6 0
3 years ago
Find the indicated probability.
natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

<u>Recall:</u>

  • Binomial Distribution --> P(k)={n\choose k}p^kq^{n-k}
  • P(k) denotes the probability of k successes in n independent trials
  • p^k denotes the probability of success on each of k trials
  • q^{n-k} denotes the probability of failure on the remaining n-k trials
  • {n\choose k}=\frac{n!}{(n-k)!k!} denotes all possible ways to choose k things out of n things

<u>Given:</u>

  • n=10
  • k=4
  • p^k=0.53^4
  • q^{n-k}=(1-0.53)^{10-4}=0.47^6
  • {n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210

<u>Calculate:</u>

  • P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0
2 years ago
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