(a + 1)(a² + 2a + 1)
= a(a² + 2a + 1) + 1(a² + 2a + 1)
= a³ + 2a² + a + a² + 2a + 1
= a³ + 3a² + 3a + 1
Answer: b
Answer:
3x−4y=9 −3x+2y=9
Add these equations to eliminate x: −2y=18
Then solve−2y=18
for y: −2y=18 −2y −2 = 18 −2 (Divide both sides by -2)
y=−9
Now that we've found y let's plug it back in to solve for x.
Write down an original equation: 3x−4y=9
Substitute−9for y in 3x−4y=9: 3x−(4)(−9)=9
3x+36=9(Simplify both sides of the equation)
3x+36+−36=9+−36(Add -36 to both sides)
3x=−27 3x 3 = −27 3 (Divide both sides by 3) x=−9
Answer: x=−9 and y=−9
Hope This Helps!!!
Answer:
x = 1 , y = 1 and z = 0
Step-by-step explanation:
-2x+2y+3z=0 ------(1)
-2x-y+z=-3 --------(2)
2x+3y+3z=5 ---------(3)
<u>To find the values of x,y and z</u>
(3) - (2)⇒ 2y + 4z = 2
y + 2z = 1 --------(4)
(1) - (2)⇒ 3y +2z =3 ---(5)
(5) - (4)⇒ 2y = 2
y = 1
Substituting the value of y in (4) we get z =0
Substituting the value of y and z in (1) we get x = 1
Therefore x = 1 , y = 1 and z = 0
Answer:
50
Step-by-step explanation:
150-100 = 50
