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aniked [119]
3 years ago
9

BRaInLiEsT tO fIrSt aNsWeR AND POINTS and my soul because math is more important....

Mathematics
1 answer:
Alex73 [517]3 years ago
6 0

D = 1/2 * (-16).  That is your answer

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Fill in the table using this function rule y=27-4x
Elis [28]

Step 1: Y= 27 - 4x

To find X - intercept / zero, substitute Y = 0

0 = 27 - 4x

Step 2: 0 = 27 - 4x

Move variable to the left-hand side and change it's sign.

4x = 27

Step 3: 4x = 27

divide both sides of the equation by 4

X = 27/4

solution: X = 27/4

Alternate form: X = 6 3/4, X = 6.75

3 0
3 years ago
T 2. If angle VST = (5x + 23)° and angle VUT = (8x - 49)º, find angle SVT. ​
ad-work [718]
2.56
it’s 2.56 because the d value
5 0
3 years ago
At a concession​ stand, three hot dog(s) and two hamburger(s) cost ​$8.00​; two hot dog(s) and three hamburger(s) cost ​$8.25. F
qaws [65]

Answer:

$1.5

Step-by-step explanation:

Solve by graphing the system of equations where x = the number of hot dogs and y = the number of hamburgers

> 3x + 2y = 8

> 2x + 3y = 8.25

The solution is (1.5, 1.75)

-- Check attachment for graph

5 0
3 years ago
-7-(-4)= helpppppp pleaseeeee
ikadub [295]

Answer:

-3

Step-by-step explanation:

-7 + 4 = -3

7 0
3 years ago
Read 2 more answers
If f(x) is a fifth degree polynomial, is it possible that it has exactly 5 complex roots?
Zolol [24]

No.

A fifth degree polynomial, having a graph that increases and starts from below x-axis.

Therefore, no matter what equation it is. The fifth degree polynomial will intercept x-axis AT LEAST one.

The fifth degree polynomial can have only at maximum, 4 complex roots.

<em>You can try drawing or seeing the graph of fifth-degree polynomial function. No matter what equations, they still intercept at least one x-value.</em>

<em />

4 0
3 years ago
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