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3 years ago

HELPPPPPPPPPPPPPPPPP!!

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

5 0

Answer:

option 3

Step-by-step explanation:

V= πr²h

to make h the subject

h= V÷πr²

just take πr² to the other side

as it in multiplication on the left hand side, it will in division in right hand side.

hope it helps!

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Martha is training for a duathlon, which includes biking and running. She knows that yesterday she covered a total distance of o

umka21 [38]

Answer:

Distance: 6x + 15.5y > 55.5

Time: x + y > 4.5

Step-by-step explanation:

We are given that Martha is training for a duathlon and she covered a total distance of over 55.5 miles in more than than 4.5 hours of training.

Also, she runs at a speed of 6 mph and bikes at a rate of 15.5 mph.

We are to write inequalities representing the distance she traveled and the total time she spent training.

Distance: 6x + 15.5y > 55.5

(formula for distance = speed x time so speeds for running and biking are multiplied by their number of hours)

Time: x + y > 4.5

(she trained for more than 4.5 hours, x hours for running and y hours for biking.

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3 years ago

How do I figure this out??

goldenfox [79]

The function is divided by 12, you would find it out by dividing 120 by 10 and getting 12, if you wanted to check your answer, you would do 84 divided by 7 which is 12. the answer to 12 is 1 and 24 is 2. hope this helped :))

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3 years ago

I need to know the opposite of 8 1/4

masya89 [10]

Well Hello!

I believe the answer to your question would be -8 1/4

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3 years ago

Read 2 more answers

First right equals brainliest, Pls dont answer for the points this is serious. I just need this and 3 more which I will ask late

Alex

I can't see the picture, can you please explain the problem in the comment bar below this so can edit my answer to help?

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3 years ago

Read 2 more answers

A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title

kirill [66]

$y' = \frac{dy}{dx}$

seperable differential equations will have the form
$\frac{dy}{dx} = F(x) G(y)$

what you do from here is isolate all the y terms on one side and all the X terms on the other
$\frac{dy}{G(y)} = F(x) dx$
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
$\int \frac{1}{G(y)} dy = \int F(x) dx

$

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it

In your problem,
$G(y) = \sqrt{1-y^2}

F(x) = 2x$

so all you need to integrate is
$\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx$

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3 years ago