X = sqrt
t = x^2
y = 2t + 5
2t = y - 5
t = (y - 5)/2
so x^2 = (y - 5) / 2
2x^2 = y - 5
y = 2x^2 + 5
Answer:
The z-score for a data value of 121 is -2.29.
Step-by-step explanation:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the z-score for a data value of 121.
This is Z when X = 121. So



The z-score for a data value of 121 is -2.29.
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