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kobusy [5.1K]
3 years ago
13

Find the volume of the large solid without the smaller solid. The solid is a right solid and is not drawn to scale. Round answer

s to the tenths place.

Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0

Answer:

b.

821.9 cube meters

Step-by-step explanation:

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Put the quadratic into vertex form and state the coordinates of the vertex. y= y= \,\,x^2-6x-3 x 2 −6x−3
enot [183]

Answer:

y = (x - 3)^2 - 12

(3,-12)

Step-by-step explanation:

Given

y = x^2 - 6x - 3

Solving (a): In vertex form

The vertex form of an equation is:

y = a(x - h)^2 + k

To do this, we make use of completing the square method.

We have:

y = x^2 - 6x - 3

------------------------------------------------------------------

Take the coefficient of x (i.e. -6)

Divide by 2; -6/2 = -3

Square it: (-3)^2 = 9

Add and subtract the result to the equation

------------------------------------------------------------------

y = x^2 - 6x - 3

y = x^2 - 6x + 9 - 9 - 3

y = x^2 - 6x + 9 - 12

Factorize x^2 - 6x + 9

y = x^2 - 3x-3x + 9 - 12

y = x(x - 3)-3(x - 3) - 12

Factor out x - 3

y = (x - 3)(x - 3) - 12

Express as squares

y = (x - 3)^2 - 12

Hence, the vertex form of y = x^2 - 6x - 3 is: y = (x - 3)^2 - 12

Solving (b): State the coordinates of the vertex.

In y = a(x - h)^2 + k; the vertex is: (h,k)

The vertex of y = (x - 3)^2 - 12 will be (3,-12)

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2 years ago
What is the total of your fixed expenses?<br><br>$1,356.08<br>$1,301.87<br>$1,401.96<br>$1,203.12
skelet666 [1.2K]

Answer:

What is the total of your fixed expenses?

Step-by-step explanation: The answer to this question which I do hope I am right is (1pt) $1,356.08


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3 years ago
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Alright a real question I need help on
andreyandreev [35.5K]
B is your answer to this question
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2 years ago
Find the distance between the two points in simplest radical form.<br> (-9,8) and (-3, -1)
dmitriy555 [2]

Answer:

The distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

Step-by-step explanation:

Given the points

  • (-9, 8)
  • (-3, -1)

Finding the distance between (-9, 8) and (-3, -1)

d\:=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

   =\sqrt{\left(-3-\left(-9\right)\right)^2+\left(-1-8\right)^2}

   =\sqrt{\left(-3+9\right)^2+\left(-1-8\right)^2}

   =\sqrt{36+81}

   =\sqrt{117}

   =3\sqrt{13} units

Therefore, the distance between (-9, 8) and (-3, -1) will be:

\:d=3\sqrt{13} units

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2 years ago
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The first one is correct
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