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3 years ago

In the number 1934 is a value of 9 in 100 place 10 times the value of the 3 in the tens place

1 answer:

8 0

no because mathematically 30X10=300 not 900 its would have to be 30X30 to get the product of 900 so therefore no your statement is incorrect

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Solve: − <− + 7( − 2) <br> (show your work)

Rashid [163]

Answer:

hope it helps.

<h2>stay safe healthy and happy...</h2>

3 0

2 years ago

3. R: {(1, 2), (2, 2), (−1, −2), (−3, 4)}?

Natali [406]

Yes it is a function Bc the x values don’t repeat

7 0

3 years ago

How many decimals in 1000

yarga [219]

Answer:

if your number is 1000 there should be one decimal at the end so it should be 1000. Because 1000. And 1000 are the same thing

Step-by-step explanation:

4 0

3 years ago

How much more would $1,000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the int

s2008m [1.1K]

Answer: There is a difference of $ 1.0228.

Explanation: Given, initial amount or principal = $ 1000,

Time= 5 years and given compound rate of interest = $3.7%

Now, Since the amount in compound continuously,

$A= Pe^{rt}$ , where, r is the rate of compound interest, P is the principal amount and t is the time.

Here, P=$ 1000, t=5 years and r= $3.7%,

Thus, amount in compound continuously , $A=1000e^{3.7\times5/100}$

⇒ $A=1000e^{18.5}=1000\times 1.20321844013=1203.21844013$

Therefore, interest in this compound continuously rate =1203.21844013-1000=203.21844013

now, Since the amount in compound quarterly,

$A=P(1+\frac{r/4}{100} )^{4t}$ , where, r is the rate of compound interest, P is the principal amount and t is the time.

Thus, amount in compound quarterly, $A=1000(1+\frac{3.7/4}{100} )^{4\times5}$

⇒ $A=1000(1+\frac{3.7}{400} )^{20}$

⇒ $A= 1202.19567617$

Therefore, interest in this compound quarterly rate=1202.19567617-1000=202.19567617

So, the difference in these interests=203.21844013-202.19567617=1.02276396 ≈1.0228

4 0

3 years ago

Read 2 more answers

The area of a baseball field bounded by home plate, first base, second base, and third base is a square. If a player at first ba

Andru [333]

Well the question doesnt show any number for a side or anything but we can solve this with algebra if we say that a side from one base to next has a length of x. so we know each side has length x and that the shape they make is square. This means we are only searching for the diagonal of a square.

remember that a diagonal forms and isoscoles right triangle with the 2 sides being equal and the diagonal as the hypotenuse. Using the pythagoream theorem we can say that
a^2 + b^2 = c^2

we said all side lengths are x so we can put x in for a and b and get

x^2 + x^2 = c^2

2x^2 = c^2

c = x * squareroot(2)

that is the basic fundamental answer that will always work when working with diagonals of squares.

so if the length between bases is 90 ft, we could plug this in and get
c = 90 ft * squareroot(2)
c = 127.28 ft

7 0

3 years ago