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german
3 years ago
8

A student studying acidity of juices did a taste test and determined that the orange juice was the sweetest juice and the lemon

and lime juices were the sourest. Based on this information, which is the best inference the student could make about acidity?
Juices with more sugar content have a lower pH.

Higher acidity causes juices to taste more sour.

Juice that tastes sour has a higher pH than juice that tastes sweet.

Lime juice tastes more sour than orange juice.
Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0
More sour juices have a higher PH because of the acid level in them.

allsm [11]3 years ago
3 0
More sour juice=high ph the cause of this is acid 
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General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

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  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
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  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
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Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

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