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mina [271]
3 years ago
12

What is the equation of the line that passes through the point (-2,-2)(−2,−2) and has a slope of 22?

Mathematics
1 answer:
quester [9]3 years ago
3 0

Answer:

Step-by-step explanation:

y-(-2)=22(x-(-2))

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PLD HELP ME IM STUCK
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We know that ∠K≅∠N & ∠L≅∠P, so that gives us 2 sets of congruent angles

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The container that holds the water for the football team is 1/2 full. after pouring in 9 gallons oo water, it is 4/5 full. how m
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8 0
3 years ago
A masonry contractor is preparing an estimate for building a stone wall and gate. He estimates that the job will take a​ 40-hour
kodGreya [7K]

Solution: Estimated time for the work is 40 hour work week.

Estimated payment to 3 laborers working 40 hours at cost $14 per hour is:

3\times 40\times 14= $1680

Estimated payment to 6 masons working 40 hours at cost $24 per hour is:

6\times 40\times 24= $5760

Estimated cost of material = $3143

Contractor wishes to make a profit of $500

Therefore, the mathematical expression that will give the estimated cost of the job is:

Cost = 1680+5760+3143+500

The estimated total cost is:

Cost =$11083




5 0
3 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let <em>X</em> = number of students who read above the eighth grade level.

(a)

A sample of <em>n</em> = 269 students are selected. Of these 269 students, <em>X</em> = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

\hat p=\frac{X}{n}=\frac{224}{269}=0.8327

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

1-\hat p=1-0.8327

        =0.1673

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

<em>n</em> = 709

<em>X</em> = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

\hat q=1-\hat p

  =1-\frac{X}{n}

  =1-\frac{546}{709}

  =0.2299\\\approx 0.229

The critical value of <em>z</em> for 95% confidence interval is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for the population proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0
3 years ago
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