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3 years ago

Hiii please help i’ll give brainliest:)

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

6 0

The answer to that would be the row ships

plz mark brainliest!

Degger [83]3 years ago

5 0

Answer:

Row ships

Step-by-step explanation:

They helped because a lot of travel took place on the Mediterranean Sea which was a massive body of water that led to the coasts of trading locations.

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Approximate the sum of the convergent infinite series the least usingnumber of terms so that the error is less than .0001. What

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Solution :

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ $a_n= \frac{(-1)^n}{n ! 2^n} \ \ \ \ \ a_{n+1}= \frac{(-1)^{n+1}}{(n+1) ! 2^{n+1}}$

Error = $|a_{n+1}|$

Error ≤ 0.0001

$|\frac{(-1)^{n+1}}{(n+1)!2^{n+1}}| \leq 0.0001$

$|\frac{1}{(n+1)!2^{n+1}}| \leq 10^{-4}$

$(n+1)! 2^{n+1} \geq 10000$

Now try, n ≥ 5

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\sum_{n=1 }^{5 } \frac{(-1)^n}{n ! 2^n}$ (with error 0.0001)

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = $\frac{-1}{1!2}+\frac{1}{2!2^2}-\frac{1}{3! 2^3}+\frac{1}{4! 2^4}-\frac{1}{5! 2^5}$

$\sum_{n=1 }^{\infty } \frac{(-1)^n}{n ! 2^n}$ = 0.6065104

3 0

3 years ago

A rocket was launched into the air from a podium 6 feet off the ground. The rocket path is represented by the equation h(t)=-16t

Arte-miy333 [17]

Answer:

Step-by-step explanation:

The given function is:

$h(t)=-16t^2+120t+6$

The average rate of change of h(t) from t=a to t=b is given by:

$\frac{h(b)-h(a)}{b-a}$

We can rewrite this function as: $h(t)=-16(t-3.75)^2+231$

The maximum height of the rocket is 231 and it occurs at t=3.75

$\implies h(3.75)=231$

The initial launch occurs at: t=0

and $h(0)=-16(0)^2+120(0)+6=6$

The average rate of change from the initial launch to the maximum height is

$\frac{h(3.75)-h(0)}{3.75-0}=\frac{231-6}{3.75-0} =60$

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3 years ago

Alondra says that (12 + 31) × 5 is equivalent to 12 + 31 × 5 because of the associative property.

Tju [1.3M]

Answer:

Step-by-step explanation:

The associative property states that you can add or multiply regardless of how the numbers are grouped.

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2 years ago

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Nikolay [14]

Answer:

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For that reason, if we have:

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3 years ago

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