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zhuklara [117]
3 years ago
5

PLEASE HELP 25 POINTS

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

Answer:Point X= 1600m, Point Z= 2050m

Step-by-step explanation:

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What is the image of (8,-6) after a reflection over the line y = x?
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Answer:

Step-by-step explanation:

Interchange x and y:  (-6, 8) is the image of (8, -6) after a reflection over y = x.

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Please help. please ​
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The Jasmine result is the good one because 1 mégas meter=1 000 000
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Which situation can be represented by this inequality?
sasho [114]

Answer:

C

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the greater than or less then symbol means at least and $425 means it has to be added in each month.

5 0
3 years ago
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Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
Give the coordinates and quadrant of Point Z.
FinnZ [79.3K]
<h2>Step-by-step explanation:</h2>
  • The two axes divide the plane into four sections called "quadrants". The quadrants are labelled with Roman numerals (not Arabic numerals), starting at the positive x-axis and going around anti-clockwise:
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3 years ago
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