Answer:
A) P(A|B) = 0.01966
B) P(A'|B') = 0.99944
Step-by-step explanation:
A) We are told that A is the event "the person is infected" and B is the event "the person tests positive".
Thus, using bayes theorem, the probability that the person is infected is; P(A|B)
From bayes theorem,
P(A|B) = [P(A) × P(B|A)]/[(P(A) x P(B|A)) + (P(A') x P(B|A'))]
Now, from the question,
P(A) = 1/400
P(A') = 399/400
P(B|A) = 0.8
P(B|A') = 0.1
Thus;
P(A|B) = [(1/400) × 0.8)]/[((1/400) x 0.8) + ((399/400) x (0.1))]
P(A|B) = 0.01966
B) we want to find the probability that when a person tests negative, the person is not infected. This is;
P(A'|B') = P(Not infected|negative) = P(not infected and negative) / P(negative) = [(399/400) × 0.9)]/[((399/400) x 0.9) + ((1/400) x (0.2))] = 0.99944
-3
0
3
those are the answers
The distance traveled by the particle between the seconds t=1 and t=3 is 14 m.
<h3>
Distance traveled by the particle</h3>
The distance traveled by the particle is determined from the model of the particle's motion.
x(t) = t² - 6t
<h3>Distance traveled when t = 1</h3>
x(1) = (1)² - 6(1) = - 5 m
<h3>Distance traveled when t = 3</h3>
x(3) = (3)² - 6(3) = -9 m
<h3>Total distance traveled by t = 1 and t = 3</h3>
D = - 5 m - 9 m = - 14 m
|D| = 14 m
Thus, the distance traveled by the particle between the seconds t=1 and t=3 is 14 m.
Learn more about distance here: brainly.com/question/4931057
#SPJ1
Answer:
If Jeff is types 5 pages at 600 words per page, then he types 3,000 words (5 x 600).
So, if Jeff started typing at 8:15 am, he'd finish at 9:30 am.
Step-by-step explanation:
The common number is 6.
72/6=12
60/6=10
12/10
simplify that, it is 6/5