Let's consider each of the options;
A) The range is the values that y can be of the function f(x). We can see that no matter what x values you put in, f(x)>0. It will never be negative. Although, if you put (1/2)^2, you can get a y value of (1/4) so this statement is incorrect.
B) It would have to put in the x or y value into the function and check. f(0)=(1/2)^0
You know that anything to the zero-th power gives 1, therefore, this statement is correct.
C) Again, if you put in a value such as (1/2)^2, you would be getting a number that is smaller than 1/2, so it isn't always increasing.
D) Again, it is possible to input any value in x and you would still be getting a positive y-value, therefore, this statement is incorrect.
Hope I helped :)
3025 is a perfect square, so just take the square root.
sqrt(3025) = 55
MAYBE COULD B (8) I guess
The -4 would be your y-intercept and the 2x would be your slope. So you would put a mark on the-4 on the y axis and go up 2 and to the right 1 to plot your line. The second one would put your starting dot on the (0,0) and go up 2 and to the right 1 to get your line. Because you would look at the 2x as 2/1x.
Hope i could help
Answer:
-9
Step-by-step explanation:
Add the cards together
2 + -6 + 1 + -2 + -4
-9