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3 years ago

Diane has $814 in her checking account. If she writes five checks for a total of $287, how much does she have left

Mathematics

1 answer:

gregori [183]3 years ago

7 0

Answer:

$527

Step-by-step explanation:

Find how much she has left by subtracting 287 from 814:

814 - 287

= 527

So, she has $527 left in her account

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3 years ago

Plz help quick How do you do this problem

astraxan [27]

Answer: $\frac{pr}{675}$

Step-by-step explanation:

cant have a negative exponent
$\frac{1}{(3p^{-1} r)^3(5pr^{-2} )^2} \\$
split up (3p^-1 r)^3
rewrite that part of the equation
$\frac{1}{(\frac{3}{p} )^{3} r^{3} }$
raise 3 to the power of 3 = 27
p to the power of 3 = $p^{3}$
Next part of the equation
$(5p)^{2}$
expand that
$5^{2} p^{2}$
simplfy
$25p^{2}$
Next part of the equation
$(r^{-2})^{2}$
multiply the exponents
$r^{-4}$
rewrite the equation
$\frac{1}{\frac{27}{p^{3} }r^{3} (25p^{2})\frac{1}{r^{4} } }$
combine $\frac{27}{p^{3} } , and , r^{3}$ = $\frac{27r^{3} }{p^{3} }$
combine 25 and $\frac{27r^{3} }{p^{3} }$
Multiply
$\frac{675r^{3} }{p^{3} }$
combine $\frac{675r^{3} }{p^{3} }$ and $p^{2}$
$\frac{675r^{3}p^{2} }{p^{3} }$
multiply $\frac{675r^{3}p^{2} }{p^{3} }$ and $\frac{1}{r^{4} }$
$\frac{1}{\frac{675r^{3}p^{2} }{p^{3}r^{4} }}$
cancel the common factors and factor everything out
$r^{3}$ comes out of ${675r^{3}p^{2} }$
$r^{3}$ can also come out of $p^{3} r^{4}$
Rewrite as $\frac{1}{\frac{675p^{2} }{p^{3} r} }$
cancel the common factor of $p^{2}$ and $p^{3}$
factor $p^{2}$ out of $675p^{2}$ by mulitiplying
factor $p^{2}$ out of ${p^{3} r} }$
cancel the common factor
rewrite the expression
$\frac{1}{\frac{675}{pr} }$
and then multiply the numerator and denominator
and you get the answer

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2 years ago