1) 200 candies
15% of my candies were strawberry candies. I had 30 strawberry candies. How many candies did i have?
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Let "x" be the number of candies.
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Equation:
0.15x = 30
x = 30/0.15
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Multiply numerator and denominator by 100 to get:
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x = 3000/15
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x = 200
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2) 146 STUDENTS
27%*T=54, So T=200.
So 200-54=146 Students passed the test.
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3) She got a 20% discount (or 80% discount). (Work shown for 80%).
First you have to find out how much Mandy paid. So from 15000 you will subtract 3000. 15000-3000=12000.
Next you need to set up your equation. . You then have to cross multiply. So 100 times 12000, 100*12000=1200000. And 15000 times x is 15000x. Finally you divide both sides by 15000. And 1200000 divided by 15000 is 80. X=80
Step-by-step explanation:
Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,
V(X)=α2σ2X¯1+β2\sigma2X¯2
Now we want to minimise this subject to α+β=1 or α−β−1=0.
We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise
f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).
We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;
∂f∂α=2ασ2X¯1+λ=0
∂f∂β=2βσ2X¯2+λ=0
∂f∂λ=α+β−1=0
Setting the first two partial derivatives equal we get
α=βσ2X¯2σ2X¯1
Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.
Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd
Answer:
the weight of the steel beam and steel beam length
let y be weight and x be length of it
y=ax
where a is the constant
we can find it if we have two sets of values of y and x
Answer:
2x
Step-by-step explanation:
x*1 is x
x/1 is also x
x+x=2x
The correct answer for this statement would be TRUE. Yes,it is true that the identity function is a linear function. <span>A linear function is a map between two vector spaces that preserves vector addition and scalar multiplication.
</span>this means f(x + y) = f(x) + f(y) and f(xy) = f(x)f(y))
<span>The identity function is the function such that f(x) = x
</span>So by using this example, we can conclude that it is a linear function.
