Answer:
701 revolutions
Step-by-step explanation:
Given: Length= 2.5 m
Radius= 1.5 m
Area covered by roller= 16500 m²
Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.
Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.
Formula; Lateral surface area of cylinder= 
Considering, π= 3.14
⇒ lateral surface area of cylinder= 
⇒ lateral surface area of cylinder= 
∴ Area covered by cylindrical roller in one revolution is 23.55 m²
Next finding total number of revolution to cover 16500 m² area.
Total number of revolution= 
Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.
Answer:
well for me it's because
Step-by-step explanation:
Of the raise to power
It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
Answer:
THE ANSWER WOULD BE TRUE MY FRIEND
Answer:
4.2π cm ≈ 13.19 cm
Step-by-step explanation:
The length s of an arc of a circle with radius r and central angle θ (in radians) is ...
s = rθ
Here, we have ...
s = (5.6 cm)(3π/4) = 4.2π cm ≈ 13.19 cm
