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nataly862011 [7]

3 years ago

13

What is the x- and y- intercepts of the following equation. -3x + 4y = -12

1 answer:

Anna71 [15]3 years ago

3 0

Answer:

i don´t know completely but i think its the 3rd one sorry if i get it wrong

hope this helps :)

Step-by-step explanation:

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Apply the distributive property to produce an equivalent expression to 10+10g?

Zolol [24]

Answer:

10(1+g)

Step-by-step explanation:

10+10g=10(1+g)

3 0

3 years ago

If the doctor’s office is 7 units from the zoo and 2 units from the park, which ordered pair could represent the location of the

s2008m [1.1K]

Answer:

(-4, -2) is the answer

Step-by-step explanation:

is you move 7 units down from the zoo you will see ur also 2 units from the park and the coordinates would be (-4, -2)

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Find the measure of arc AC whose inscribed angle is 62 degrees.

Marina CMI [18]

Check the picture below, that's the "inscribed angle theorem"

3 0

3 years ago

How do you find the area of a triangle???? PLEASE HELP

irinina [24]

Answer:

find the base 1st then Height.You should be able to get your Area after doing those steps correctly

3 0

3 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago