Split up each force into horizontal and vertical components.
• 300 N at N30°E :
(300 N) (cos(30°) i + sin(30°) j)
• 400 N at N60°E :
(400 N) (cos(60°) i + sin(60°) j)
• 500 N at N80°E :
(500 N) (cos(80°) i + sin(80°) j)
The resultant force is the sum of these forces,
∑ F = (300 cos(30°) + 400 cos(60°) + 500 cos(80°)) i
… … … + (300 sin(30°) + 400 sin(60°) + 500 sin(80°)) j N
∑ F ≈ (546.632 i + 988.814 j) N
so ∑ F has a magnitude of approximately 1129.85 N and points in the direction of approximately N61.0655°E.
Answer:
Answer as follows...
Step-by-step explanation:
interior angles are 3,4,5,6
exterior angles are 1,2,7,8
vertical angles are 2and3, 1and4, 6and7, 5and8
corresponding angles are 2and6 1and5 3and7 4and8
alternate interior angles are 4and5 3and6
alternate exterior angles are 1and8 2and7
same side interior angles are 3and5 4and6
