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2 years ago

Solve the right triangle. round your answers to the nearest tenth. help.

Mathematics

1 answer:

hammer [34]2 years ago

8 0

Answer:

19.2

Step-by-step explanation:

Cosine rule :

$\sqrt{a^{2} +b^{2} ﹣2abcos(angle ) }$

c will always be the hypotenuse.

a and b can be any if the opposite or the adjacent.

${15}^{2} + 12^{2} - 2 \times 15 \times 12 \times \cos(90) = 369$

\sqrt{369}=19.20937...

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2 years ago

13 out of 60 people surveyed were left handed calculate the angle you would use in a pie chart

PtichkaEL [24]

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3 years ago

What is 160/11 as a whole number

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Step-by-step explanation:

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2 years ago

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A recipe includes 8 cups of flour and 2/3 third cups of sugar right the ratio of the amount of flour to the amount of sugar as a

Art [367]

Its 8:2/3, we can write it as $\frac{8}{ \frac{2}{3} } =8 *\frac{3}{2} = \frac{8*3}{2} = \frac{24}{2}= \frac{12}{1}$
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3 years ago

If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)

belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If $h(x)=\frac{f(x)}{g(x)}$ , then:

$h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}$

Since in our case we want the derivative of $h(x)$ at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}$

which, by replacing with the given numerical values:

$f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3$

becomes:

$h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0$

3 0

2 years ago