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VashaNatasha [74]

3 years ago

12

How do you solve for x when x squared = 9?

1 answer:

ASHA 777 [7]3 years ago

5 0

If the squared number be 9 from a squared the x would = 18 right?

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Outcomes for what tho exactly?

8 0

3 years ago

For what value(s) of k will the relation not be a function

skelet666 [1.2K]

We are given two relations

(a)

Relation (R)

$R=[((k-8.3+2.4k),-5),(-\frac{3}{4}k,4)]$

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$k-8.3+2.4k=-\frac{3}{4} k$

$3.4k-8.3=-\frac{3}{4}k$

$3.4k\cdot \:10-8.3\cdot \:10=-\frac{3}{4}k\cdot \:10$

$4k-83=-\frac{15}{2}k$

$34k=-\frac{15}{2}k+83$

$\frac{83}{2}k=83$

$83k=166$

$k=2$ ............Answer

(b)

S = {(2−|k+1| , 4), (−6, 7)}

We know that

any relation can not be function when their inputs are same

so, we can set both x-values equal

and then we can solve for k

$2-|k+1|=-6$

$2-\left|k+1\right|-2=-6-2$

$-\left|k+1\right|=-8$

$\left|k+1\right|=8$

Since, this is absolute function

so, we can break it into two parts

$|f\left(k\right)|=a\quad \Rightarrow \:f\left(k\right)=-a\quad \mathrm{or}\quad \:f\left(k\right)=a$

$k+1=-8\quad \quad \mathrm{or}\quad \:\quad \:k+1=8$

we get

$k+1=-8\quad$

$k=-9$

$k+1=8\quad$

$k=7$

so,

$k=-9\quad \mathrm{or}\quad \:k=7$ ...............Answer

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3 years ago

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Given that S<span>hanley would like to give $5 gift cards and $4 teddy bears as party favors and that Shanley has $128 to spend on party favors.

The inequality to find the number of </span><span>gift cards x and teddy bears y Shanley could purchase</span> is given by

$5x+4y\leq128$

One solution to the inequality is that Shanley can buy 12 gift cards and 15 teddy bears.

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Given that f(x) = x2 + 9x + 18 and g(x) = x + 6, find f(x) – g(x) and

Diano4ka-milaya [45]

Answer:

x^2+8x+12

Step-by-step explanation:

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