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kaheart [24]
3 years ago
10

Six movie tickets cost $54.

Mathematics
2 answers:
asambeis [7]3 years ago
6 0
$9.00 for one ticket. Just divide 6 by the $54.00
enot [183]3 years ago
5 0
One movie ticket coast 9 dollars.
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Suppose the shipping company were packing balls with a diameter of 2 inches instead of cubes. Would the large box hold more ball
Roman55 [17]

Answer:

More

Step-by-step explanation:

Because the absence of corners allows more space for more balls

8 0
3 years ago
What is a number with one or more digits to the right of the decimal point called?
velikii [3]

Answer:

hm if it were in fraction form it would be called a mixed number but if not the it would be either tenths hundredths thousandths these three would be the most common of them all

Step-by-step explanation:


7 0
3 years ago
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Can you please solve number 49? thank you in advance
Ivanshal [37]

Answer:

Option (c) is correct.

Step-by-step explanation:

See the attached figure.

Here, x + y = 10 cm. ............ (1)

The height h divides the whole right triangle into two different right triangles.

If we consider the height as h, then applying Pythagoras Theorem,  

h² = 6² - x² {From small triangle} ........... (2)

Again, from large triangle we can write,

h² = 8² - y² .............. (3)

Now, from equation (2) and (3) we can write  

6² - x² = 8² - y²

⇒ 36 - x² = 64 - (10 - x)² {From equation (1)}

⇒ 36 - x² = 64 - 100 - x² + 20x

⇒20x = 72

⇒ x = 3.6 cm.

So, from equation (1) we get, y = 10 - 3.6 = 6.4 cm.  

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4 0
4 years ago
Write and equation of the translated or rotated graph in general form (picture below)
WINSTONCH [101]

Answer:

The answer is hyperbola; (x')² - (y')² - 16 = 0 ⇒ answer (a)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

 xy = -8

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* The equation xy = -8

∵ We have term xy that means we rotated the graph about

  the origin by angle Ф

∵ Ф = π/4

∴ We rotated the x-axis and the y-axis by angle π/4

* That means the point (x' , y') it was point (x , y)

- Where x' = xcosФ - ysinФ and y' = xsinФ + ycosФ

∴ x' = xcos(π/4) - ysin(π/4) , y' = xsin(π/4) + ycos(π/4)

∴ x' = x/√2 - y/√2 = (x - y)/√2

∴ y' = x/√2 + y/√2 = (x + y)/√2

* Lets substitute x' and y' in the 1st answer

∵ (x')² - (y')² - 16 = 0

∴ (\frac{x-y}{\sqrt{2}})^{2}-(\frac{x+y}{\sqrt{2}})^{2}=

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* Lets open the bracket

∴ \frac{x^{2}-2xy+y^{2}-x^{2}-2xy-y^{2}}{2}-16=0

* Lets add the like terms

∴ \frac{-4xy}{2}-16=0

* Simplify the fraction

∴ -2xy - 16 = 0

* Divide the equation by -2

∴ xy + 8 = 0

∴ xy = -8 ⇒ our equation

∴ Answer (a) is our answer

∴ The answer is hyperbola; (x')² - (y')² - 16 = 0

* Look at the graph:

- The black is the equation (x')² - (y')² - 16 = 0

- The purple is the equation xy = -8

- The red line is x'

- The blue line is y'

6 0
4 years ago
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3) Find the midpoint of the line segment with endpoints (-3, 2) and (1, -2) .
Gala2k [10]
(-3,2)
(-2, 1)
(-1, 0)  <-----
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(1, -2)

Midpoint is (-1, 0)
4 0
3 years ago
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