3 years ago

Is (7. - 1) a solution of y = x -8? Yes No

Mathematics

1 answer:

tresset_1 [31]3 years ago

5 0

Answer:

Yes

Step-by-step explanation:

Substitute the x and y values in for x and y to check.

-1 = 7 - 8

-1 = -1

In this instance, (7, -1) is a solution of y = x - 8.

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7x+7y=42;x how do u solve this problem

Oxana [17]

The slope would be -x+6 & m=-1

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3 years ago

If s(x)=2-x^2 and t(x)=3x, which value is equivalent to (s*t)(-7)?

andreyandreev [35.5K]

Answer:

(s*t)(-7) = 987

Step-by-step explanation:

s(x) = 2 - x²

t(x) = 3x

To find (s*t)(x), multiply s(x) and t(x).

(s*t)(x) = (2 - x²)(3x)

(s*t)(x) = 6x - 3x³

Now that you have (s*t)(x), plug -7 in.

(s*t)(-7) = 6(-7) - 3(-7)³

(s*t)(-7) = 6(-7) - 3(-343)

(s*t)(-7) = -42 + 1029

(s*t)(-7) = 987

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4 years ago

If each cube has edges .5 inches long, what is the volume of the prism?

Gre4nikov [31]

.20 is the correct answer

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3 years ago

Read 2 more answers

How the balls did .7511030598245 become 49 DEGREES??

ycow [4]

Is your calculator in radian mode??? Check that first.

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4 years ago

A ball is launched straight up in the air from a height of 6 feet. Its velocity (feet/second) t seconds after launch is given by

german

Step-by-step explanation:

A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :

f(t) = -32 t+285

Height of the ball is :

$h(t)=\int\limits{f(t){\cdot} dt}\\\\h(t)=\int\limits{(-32t+285){\cdot} dt}\\\\h(t)=-16t^2+285t+C$

C is constant. Here the ball is launched from a height of 6 feet. So,

$h(t)=-16t^2+285t+6$

At t = 2 s, $h(t)=-16(2)^2+285(2)+6=512\ m$

At t = 9 s, $h(t)=-16(9)^2+285(9)+6=1275\ m$

Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.

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4 years ago