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3 years ago

12

Help me pls pls help

2 answers:

Lelu [443]3 years ago

8 0

Answer:

third one is a required answer.

x =2y

or

1/x=y

mylen [45]3 years ago

7 0

Answer:

Option 3, where x = 6, y = 3; x = 10, y = 5; x = 14, y = 7

Step-by-step explanation:

<u>Step 1: Define proportional relationship</u>

According to Khan Academy, "proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other."

<u>Step 2: Find the proportional relationship</u>

Looking at option 3, we see that x is always 2 times bigger than y. This means as y increases, x is twice that amount. So if y is 10, x would be 20 and so on. Therefore, Option 3 is the correct answer.

Answer: Option 3, where x = 6, y = 3; x = 10, y = 5; x = 14, y = 7

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3 years ago

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Thirty-five percent of what number is 10.5?

erastovalidia [21]

30% of 35 = 10.5

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solong [7]

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Step-by-step explanation:

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3 years ago

Fill in the missing information. Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 w

nlexa [21]

Answer:

$P(38.6$

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

$z=\frac{X -\mu}{\sigma}$

And replacing we got:

$z=\frac{38.6- 45}{16}= -0.4$

$z=\frac{57.8- 45}{16}= 0.8$

We can find the probability of interest using the normal standard table and with the following difference:

$P(-0.4$

Step-by-step explanation:

Let X the random variable who represent the expense and we assume the following parameters:

$\mu = 45, \sigma 16$

And for this case we want to find the percent of his expense between 38.6 and 57.8 so we want this probability:

$P(38.6$

And we can assume a normal distribution and then we can solve the problem with the z score formula given by:

$z=\frac{X -\mu}{\sigma}$

And replacing we got:

$z=\frac{38.6- 45}{16}= -0.4$

$z=\frac{57.8- 45}{16}= 0.8$

We can find the probability of interest using the normal standard table and with the following difference:

$P(-0.4$

6 0

3 years ago

On Thursday a local shop sold a combination of 417 hamburgers and cheese burgers. The number of cheeseburgers sold was two times

seropon [69]

Answer:

The number of hamburgers sold was 139 and the number of cheeseburgers sold was 278.

Step-by-step explanation:

Let

x -----> the numbers of hamburgers sold on Thursday

y -----> the numbers of cheeseburgers sold on Thursday

we know that

$x+y=417$ ----> equation A

$y=2x$ ----> equation B

Substitute the equation B in equation A and solve for x

$x+2x=417$

$3x=417$

$x=139$

Find the value of y

$y=2(139)=278$

therefore

The number of hamburgers sold was 139 and the number of cheeseburgers sold was 278.

8 0

3 years ago