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Paha777 [63]
3 years ago
12

If six time a number is decreased by 10 the result is 50. Find the number

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Step-by-step explanation:

50 = 6x - 10

+ 10 + 10

60 = 6x

/6 /6

10 = x

alina1380 [7]3 years ago
5 0
6x -10 = 50
6x = 60
x = 10
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Kendall is making greeting cards, which she will sell by the box at an arts fair. She paid $40
natta225 [31]

Answer:

9

Step-by-step explanation:

40 dollars due up front

10 dollars made per sale

5 dollars lost per creation

Realistically speaking she is only making a $5 profit per box she sells;

<em>$5 used up for material cost, $10 made from sales </em><em>-5+10= 5</em>

To pay the $40 dollar for the booth she would need to make 9 sales with her current profit

<em>40/5 = 9</em>

5 0
3 years ago
Suppose the standard deviation of a normal population is known to be 3, and H0 asserts that the mean is equal to 12. A random sa
blagie [28]

Answer:

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

p_v =P(z>1.9)=0.0287  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=12.95 represent the sample mean

\sigma=3 represent the population standard deviation for the sample  

n=36 sample size  

\mu_o =12 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 12, the system of hypothesis would be:  

Null hypothesis:\mu \leq 12  

Alternative hypothesis:\mu > 12  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{12.95-12}{\frac{3}{\sqrt{36}}}=1.9  

P-value  

Since is a right tailed test the p value would be:  

p_v =P(z>1.9)=0.0287  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 12 at 5% of signficance.  

4 0
3 years ago
Read 2 more answers
9 cm<br> 4 cm<br> Fine the area
Lelechka [254]

Answer:

area formula: base x height 9x4=36

Step-by-step explanation:

7 0
3 years ago
Find the GCF of 56x3y and 28xy2
azamat
Xy is the GCF of these expressions
6 0
3 years ago
Willie and anjali each improved their yards by planting daylilies and ivy. They bought their supplies from the same store. Willi
Fiesta28 [93]

Answer:the cost of one day lily = $9 and cost of one pot of ivy = $2

Step-by-step explanation:

Step 1

let day lilies be rep as d

and ivy be represented as i

So that The expression for what Willie spent on  12 day lilies and 4 pots of ivy = $116 be

12 d+ 4i = 116 ---- equation 1

and for Anjali spending  $60 on 6 day lilies and 3 pots of ivy be

6d+ 3i = $60------ equation 2

Step 2 --- Solving

 12 d+ 4i = 116 ---- equation 1

6d+ 3i = $60------ equation 2

Multiply equation 2 by (2) and subtracting equation 1  from it

12d+ 6i= 120

--12 d+ 4i = 116

2 i= 4

i = 4/2 = 2

TO find d, putting the value of i = 2 in equation 1 and solving

12d+ 4(2) = 116

12d= 116-8

12d= 108

d= 108/12= 9

Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2

5 0
3 years ago
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