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2 years ago

Which is the simplified form of the expression

Mathematics

1 answer:

erica [24]2 years ago

3 0

Answer:

4 / x¹⁴y⁸

Step-by-step explanation:

eliminate parenthese by multiplying all exponents inside parentheses by the exponent outside the parentheses:

1/2⁶ ÷ 1/4⁴ = 1/64 ÷ 1/256 which equals 256/64 or 4

x⁻⁶y⁴ ÷ x⁸y¹² = x⁻¹⁴y⁻⁸ = 1/x¹⁴ · 1/y⁸

put it all together to get:

4÷(x¹⁴y⁸)

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Find the Area of the figure below, composed of a rectangle with two semicircles removed. Round to the nearest tenths place.

Allisa [31]

Answer:

21.8

Step-by-step explanation:

hii so basically first we find the area of the 9 by 8 and subtract the area of the semicircles.

area of circles are πr^2, so in this situation

π4^2 which is 16π.

with this, the semicircle which is half a circle would give us

16π/2 which is 8π.

but then, we have two semicircles removed so we would have as an answer:

(9*8)-8π+8π

72-16π

then you would have to round so

16π is around 50.2

so 72-50.2 is 21.8

i hope this helped you <33

6 0

2 years ago

Which statements are true about the linear inequality y > x – 2? Check all that apply.

Firdavs [7]

the graph intercepts the y axis o,-2

7 0

2 years ago

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a factory produces toy dolls at a rate of 400 per hour and has to recycle 3% of them because the clothes are torn. express the r

AnnyKZ [126]

12
3/100 = 0.03
0.03x400 = 12
12 dolls are recycled per hour

4 0

2 years ago

Rewrite 2 4/7 as an improper fraction

Nataliya [291]

2 = 14 now add the extra 4/7 and you will get 18/7.
7

2 4
 7 using the algorithm (a shortcut way) 2x7=14+4=18 and put that 18 over the denominator 7. Done!

3 0

2 years ago

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Multiply: 4x * root(3, 4x ^ 2) * (2 * root(3, 32x ^ 2) - x * root(3, 2x))

Salsk061 [2.6K]

Answer:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

Step-by-step explanation:

We want to

$4x \sqrt[3]{4 {x}^{2} } (2 \sqrt[3]{32 {x}^{2} } - x \sqrt[3]{2x} )$

We expand to obtain:

$4x \sqrt[3]{4 {x}^{2} } \times 2 \sqrt[3]{32 {x}^{2} } -4x \sqrt[3]{4 {x}^{2} } \times x \sqrt[3]{2x} )$

We now simplify

$8x \sqrt[3]{4 {x}^{2} \times 32 {x}^{2} } -4 {x}^{2} \sqrt[3]{4 {x}^{2} \times 2x}$

We multiply the radicand

$8x \sqrt[3]{64 \times {x}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{8 {x}^{3}}$

$8x \sqrt[3]{ {(4x)}^{3} \times 2x } -4 {x}^{2} \sqrt[3]{{(2x)}^{3}}$

We take cube root to get:

$8x \times 4x\sqrt[3]{ 2x } -4 {x}^{2} \times 2x$

We multiply out to get:

$32 {x}^{2} \sqrt[3]{ 2x } -8{x}^{3}$

6 0

2 years ago

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