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Julli [10]
3 years ago
12

HELP ASAP TEST SOON IMMA FAIL THAT B! HELLLPPPPP! DUE IN 10 MINS HELP! 1. What equation is represented on the graph below?

Mathematics
1 answer:
eduard3 years ago
6 0

Step-by-step explanation:

1 is the starting point since it is on the the axis.

then you would use the rise over run method to get the fraction. it rises by two and runs by 1 which would get you 2/1. so the answer should be y=1+2/1

(it is an addition sign since it is a positive slope)

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The area of a rectangle is equal to its length times its width. If the area of a rectangle
Pepsi [2]

Answer:

d

Step-by-step explanation:

8 0
3 years ago
Hi I was having some problem with this question, its been a while since I had been in geometry. I think you foil, but Im not sur
DochEvi [55]
First, I would distribute the 2 out to the (x+4). 

2x+8. 

Next, use the foil method to multiply together 2x+8 and (x+3). 

2x^2 +14x+24. 

Do the same process for the other side. 

3(x+2)= 3x+6 

(3x+6)(x-1)= 3x^2+3x-6

Set the remaining products of each side of the equation equal to each other. 

2x^2 +14x+24=3x^2+3x-6. 

Now you must cancel out one side to make the equation equal to zero. Do this by doing the inverse operation on one side of the equation (each value with their like term). I am going to subtract the left side values from the right: 

This means: 
3x^2 minus 2x^2 equals 1x^2 (or just x^2).    

3x minus 14x equals -11x 

-6 minus 24 equals -30 

The equation should now look like this: 

0=x^2-11x-30

Reverse the order to get zero on the right side: 

x^2-11x-30=0

Hope this helps! Sorry if I made any careless mistakes (^^;)


7 0
4 years ago
(a) Complete the table of values for y = 6 - 4x.<br><br> Please help ❤️
shutvik [7]

<u>Answer:</u>

\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}

<u>Step-by-step explanation:</u>

Given equation to us is :-

\implies y = 6 - 4x

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>(</u><u>-</u><u>1</u><u>)</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }

<u>Put</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u>

\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}

<u>Hence </u><u>the</u><u> </u><u>final</u><u> </u><u>table</u><u> </u><u>would</u><u> </u><u>be</u><u> </u><u>:</u><u>-</u><u> </u>

\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}

4 0
3 years ago
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lys-0071 [83]

Answer:

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Step-by-step explanation:

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There are 64 pencils in a pack. Mr. Math is the only teacher to give out pencils on day one and
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Answer:

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