Answer:
x=10/3
Step-by-step explanation:
Answer: i
Step-by-step explanation:
i2 = −1i3 = i2 x i = −1 x i = −ii4 = i2 x i2 = −1 x −1 = 1Hence, i233 =i4 x 58 + 1 = i232 x i1 = 1 x i = i
<h3>The volume of a hexagonal-based prism is 744 cubic inches</h3><h3>No the volume will not be different</h3>
<em><u>Solution:</u></em>
Given that,
Hexagonal-based prism with a height of 12 in. and a base area of 62 square inches
<em><u>The volume of prism is given as:</u></em>

Thus volume of a hexagonal-based prism is 744 cubic inches
Would the volume be different if the base were a pentagon with an area of 62 in² ?
No the volume will not be different
The shape of base does not matter, as long as the base area is same
Thus, volume of hexagonal-based prism and pentagon prism with area 62 inches is 744 cubic inches
Answer:
the greatest number of marbles that was collected is bt Dalton
Answer:
W(-2, -3), X(-6, -3)
, Y(-6, -4) and Z(-3, -5)
Step-by-step explanation:
In the figure attached, the quadrilateral W'X'Y'Z' is shown. Its coordinates are W'(2, 3), X'(6, 3), Y'(6, 4) and Z'(3, 5). Transforming these points according to the rule (x,y) → (-x, -y) we can get the pre-image, quadrilateral WXYZ, as follows:
W'(2, 3) -> W(-2, -3)
X'(6, 3) -> X(-6, -3)
Y'(6, 4) -> Y(-6, -4)
Z'(3, 5) -> Z(-3, -5)