The set of side lengths that form a right triangle is 7, 24, 25
Explanation:
We can solve this using the Pythagorean Theorem. The Pythagorean Theorem states that in a right triangle, a^2 + b^2 = c^2. We can plug each set of numbers into the equation, one by one, to see if the set of numbers is true in the equation. One thing to note is that the largest number out of the set is always the hypotenuse, or c. The other numbers are the legs (a and b.)
5, 11, 13
a^2 + b^2 = c^2
(5)^2 + (11)^2 = (13)^2
25 + 121 = 169
146 ≠ 169
Since 146 doesn't equal 169, this is NOT a right triangle
9, 24, 25
a^2 + b^2 = c^2
(9)^2 + (24)^2 = (25)^2
81 + 576 = 625
657 ≠ 625
Since 657 doesn't equal 625, this is NOT a right triangle
7, 24, 25
a^2 + b^2 = c^2
(7)^2 + (24)^2 = (25)^2
49 + 576 = 625
625 = 625
This equation is true, because 625 = 625. Therefore this IS a right triangle.
Problem # 1
3w-10=4w+5
(3w-10) + (10-4w) = (4w+5) + (10-4w)
(3w-10) + (-4w+10) = (4w+5) + (-4w +10)
3w-10-4w+10 = 4w +5 -4w +10
3w-4w=15
-w=15
w= -15 (w is negative 15)
problem #2.
6-2t > 18
6-2t-6 > 18-6
-2t > 12
(-1) (-2t) > 12 (-1)
2t > -12
next divide by 2
2t/2 > -12/2
t > -6 (t is greater then negative 6)
Answer:
Quadratic function
Step-by-step explanation:
If two squares have different perimeters, the one with the larger perimeter will have a larger area. If two polygons have the same perimeter, then they must have the same shape. If two polygons have the same shape but are different sizes, then they must have different perimeters.
If two squares have equal areas, they will also have sides of the same length. But although "equal areas mean equal sides" is true for squares, it is not true for most geometric figures.
In order to find the perimeter or distance around the rectangle, we need to add up all four side lengths. This can be done efficiently by simply adding the length and the width, and then multiplying this sum by two since there are two of each side length.
Learn more about perimeter at
brainly.com/question/397857
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