We use quadratic formula then
For a expression
The quadratic formula is
If underroot values becomes negative we use iota(i)
which has value=√-1
2x + 3 = 4x + 2
3 - 2 = 4x - 2x
1 = 2x
x = 1/2
Its B 1 solution
Answer:
71.25 (or 71 1/4) mi
Step-by-step explanation:
15/4 = 3.75
1 in = 3.75 mi
3.75 × 19 = 71.25 mi
9514 1404 393
Answer:
45. (8√2)∠π/4
46. (7√2)∠3π/4
Step-by-step explanation:
The polar form of a+bi is ...
a +bi ⇔ (√(a²+b²))∠arctan(b/a)
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45. 8 +8i = (√(8² +8²))∠arctan(8/8) = (8√2)∠π/4
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46. -7 +7i = (√((-7)² +7²))∠arctan(7/-7) = (7√2)∠3π/4
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<em>Additional comment</em>
The arctan function usually returns a value in the range -π/2 to π/2. The quadrant of the desired result can be determined by the signs of the components of the vector. For negative real parts, π needs to be added to the value that is usually returned by the arctan function.