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Y_Kistochka [10]
2 years ago
13

Find the radius of a sphere with a volume of 972π cubic millimeters.

Mathematics
2 answers:
sesenic [268]2 years ago
8 0

Answer:

The radius is 9 mm

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3  where r is the radius

972 pi  = 4/3 pi r^3

Divide each side by pi

972 = 4/3 r^3

Multiply each side by 3/4 to isolate r^3

3/4 * 972 = 4/3 * 3/4 r^3

729 = r^3

Take the cube root of each side

(729) ^ (1/3) = (r^3) ^ (1/3)

9 = r

The radius is 9 mm

soldier1979 [14.2K]2 years ago
6 0

Answer:

9 mm

Step-by-step explanation:

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Whats the answer giving brainliest :)>.
elena-s [515]

Answer:

B is the correct answer :))

because she's doing the math so that there are 40 plants in each row. So, she's trying to figure out how many rows she will need. When she does the math for 40 plants in each row, she ends up with 193 rows, and 25 corn plants left over

Step-by-step explanation:

7 0
3 years ago
Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2
Marat540 [252]

Given:

The point, (4, -3)

The line,

y=\frac{1}{2}x+5

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

m=\frac{1}{2}

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

y-y_1=m(x-x_1)

Substitute the point and slope we get,

\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}

Hence, the equation in slope-intercept form for the line is,

y=\frac{1}{2}x-5

8 0
1 year ago
Given the data, as shown in the image below, determine if the distribution is uniformly distributed, symmetrically distributed,
Sedbober [7]

Answer:

The distribution is symmetric.

Step-by-step explanation:

<em>The distribution will be skew left, if the data is more distributed on left side of graph.</em>

<em>The distribution will be right left, if the data is more distributed on right side of graph.</em>

<em>The distribution is symmetric if from the center, the data is distributed symmetrically, equal increase or decrease on either side.</em>

<em>The distribution is uniform if the value of data remains constant throughout the graph.</em>

Above here, the from the center, the data decreases symmetrically on both the sides, same values of data for Cat-Rabbit pair and Dog-Mice pair.

Thus, distribution is symmetric.

8 0
3 years ago
Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua
goblinko [34]
<h2>Hello!</h2>

The answer is:  There is a total of 5.797 gallons pumped during the given period.

<h2>Why?</h2>

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

D(t)=\frac{5t}{1+3t}

So, the integral will be:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dx

So, integrating we have:

\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx

Performing a change of variable, we have:

1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}

Then, substituting, we have:

\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du

\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )

\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du

\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]

Reverting the change of variable, we have:

\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]

Then, evaluating we have:

\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0
3 years ago
Expand -8(4p-7) please
Artemon [7]

Answer:

-32p+56

Step-by-step explanation:

-8*4p=-32p

-7*-8=56(negative times negative =positive)

-32p+56

3 0
2 years ago
Read 2 more answers
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