Answer:
($2.123 ; $2.149)
Step-by-step explanation:
The prediction interval is expressed as :
Predicted value ± standard Error
Predicted value = $2.136
Standard Error = $0.013
Prediction interval :
Lower boundary = $2.136 - $0.013 = $2.123
Upper boundary = $2.136 + $0.013 = $2.149
($2.123 ; $2.149)
B.) The prediction interval provides a range for which the predicted value or price should fall Given a certain degree of probability. If the true value falls within this interval, then, our prediction would be deemed to have occurred not by chance.
Since the actual price within the predicted price interval, then I agree with the judge's Decison that the price was not artificially depressed.
Answer:
In 9 days will the second warehouse have 1.5 times more coal than the first one
Step-by-step explanation:
The coal left in warehouses after x days can be found using the equation:
- first warehouse: 185 - 15x
- second warehouse= 237-18x
Let the second warehouse have 1.5 times more coal than the first one after n days then
- 1.5 ×(185 - 15n)=237-18n which gives:
- 277,5-22,5n=237-18n and
- 40,5=4,5n
- 9=n
<h2>19.</h2><h3>Given</h3>
- window width and height are in proportion to building width and height
- window width and height are 11 in and 18 in, respectively
- building height is 108 ft
<h3>Find</h3>
<h3>Solution</h3>
The proportional relation can be written as
... (building width)/(building height) = (window width)/(window height)
Multiplying by (building height) gives
... (building width) = (building heigh) × (window width)/(window height)
... (building width) = 108 ft × (11 in)/(18 in)
... building width = 66 ft
<h2>21.</h2><h3>Given</h3>
- map distance = 6.75 in
- map scale = 1.5 in : 5 mi
<h3>Find</h3>
<h3>Solution</h3>
The distances are in proportion, so
... (map distance) : (actual distance) = 1.5 in : 5 mi
Multiplying by (5 mi)/(1.5 in)×(actual distance), we have
... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi
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