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svet-max [94.6K]
3 years ago
6

A ball as a radius of 18cm. What is the approximate volume of the ball?

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

what I got was 24438.9cm³

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Which is true regarding the graphed function f(x)?
mojhsa [17]
F(5) = -1 would be the correct answer.
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2 years ago
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What is the square root of 49.<br> a. 7<br> a.<br> b. 6<br> C. 8<br> 2 d. 9
Mashcka [7]

Answer:

a. 7

Step-by-step explanation:

7x7=49

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3 years ago
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A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
3 years ago
What is the product of the polynomials below? (6x3 + 3x)(x2 + 4)
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I spent $10 dollars out $25 what is percent I spent
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\text {Percentage spent = }  \dfrac{10}{25} \times 100

\text {Percentage spent = }  \dfrac{2}{5} \times 100

\text {Percentage spent = }  40 \%
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