Answer=49
The dot in the middle represents the median
Answer:
16
Step-by-step explanation:
Put the numbers where the variables are and evaluate:
F(3) = 2(3)^2 +1 = 19
G(4) = 2(4) -1 = 7
H(5) = 5
Then the desired sum is ...
F(3) +G(4) -2H(5) = 19 +7 -2(5) = 16
Answer:
a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Person has type A blood.
Event B: Person has Rh- factor.
43% of people have type O blood
This means that 
15% of people have Rh- factor
This means that 
52% of people have type O or Rh- factor.
This means that 
a. Find the probability that a person has both type O blood and the Rh- factor.
This is

With what we have

0.06 = 6% probability that a person has both type O blood and the Rh- factor.
b. Find the probability that a person does NOT have both type O blood and the Rh- factor.
1 - 0.06 = 0.94
0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.
Answer:
False
Step-by-step explanation:
a millisecond (ms or msec) is one thousandth of a second