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3 years ago

What is the answer to 2log3(x)=4?

Mathematics

1 answer:

Marysya12 [62]3 years ago

8 0

Answer:

x ≈ 4.19180

Step-by-step explanation:

$2 log 3(x) = 4$

$2 log(3)(x) = 4$

Divide both sides by 2log (3) to isolate x by itself

$\frac{2log(3)(x)}{2log(3)} = \frac{4}{2log(3)}$

$x = \frac{4}{2log(3)}$

or x ≈ 4.19180

using a calculator you can write the answer as a rounded number

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HELP PLEASE

Maurinko [17]

$\bf \cfrac{x^2-x-42}{x-6}\implies \cfrac{(x+7)\underline{(x-6)}}{\underline{x-6}}\implies x+7$

so.. the left-hand-side does indeed simplify to x+7, so the equation does check out.

however, notice something, for the equation of x+7, when x = 6, we get (6) + 7 which is 13.

BUT for the rational, we get $\bf \cfrac{x^2-x-42}{x-6}\qquad \boxed{x=6}\implies \cfrac{x^2-x-42}{\boxed{6}-6}\implies \stackrel{und efined}{\cfrac{x^2-x-42}{0}}$

so, even though the siimplification is correct, the rational or original expression is constrained in its domain.

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3 years ago

Find m∠LKE. m∠LKJ = 150° m∠LKE = (x + 32)° m∠EKJ = (x + 94)° A) 40° B) 44° C) 46° Eliminate D) 48°

Luden [163]

Answer:

B) 44°

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Help!! !, is it right or not

Dahasolnce [82]

Answer:

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

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2 years ago

What is an equation of the line that passes through the point (-6,-8) and is parallel to the line x-2y=6?

vfiekz [6]

Answer:

$y=\frac{1}{2}x-5$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)
Parallel lines always have the same slope and different y-intercepts

1) Determine the slope (m)

$x-2y=6$

Rearrange this equation into slope-intercept form (this will help us find the slope)

Subtract x from both sides

$x-2y-x=6-x\\-2y=-x+6$

Divide both sides by -2

$y=\frac{1}{2} x-3$

Now, we can identify clearly that the slope of the given line is $\frac{1}{2}$ since it's in the place of m. Because parallel lines always have the same slopes, the line we're currently solving for would therefore have a slope of $\frac{1}{2}$ as well. Plug this into $y=mx+b$ :