Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
Step-by-step explanation:
7p – 3q
if p= 8 and q = -5
7(8)-3(-5)
56+15
=71
-7x + 6 = 27
-7x = 21 (Subtract 6 from both sides)
x = -3 (Divide -7 from both sides)
Answer: Choice A
y + 1 = -3(x+2)
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Explanation:
Let's look through the answer choices.
Choices C and D show that the point (2,1) is on the line. But the graph does not show this. So we can rule out choices C and D.
With choice A, the slope is negative and choice B has a positive slope.
The answer must be choice A because the line is going downhill as we move from left to right.
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A common method is to pick two points on the line and compute the slope using the slope formula
m = (y2-y1)/(x2-x1)
Once you know the slope, you would use point slope form
y - y1 = m(x - x1)
