Hello, i wanted to know how to do this. Thank you.

Mathematics

2 answers:

ZanzabumX [31]3 years ago

8 0

Answer:

multiply the number within parenthesis by itself the number of times equivalent to the exponent.

for example

1) 6^3 = 6*6*6 = 216

2) 4^2 = 4*4 = 16

3) 9^3 = 9*9*9 = 729

4) 8^3 = 8*8*8 = 512

5) 3^3 = 3*3*3 = 27

6) 2^3 = 2*2*2 = 8

7) 7^3 = 7*7*7 = 343

8) 5^3 = 5*5*5 = 125

9) out of frame

10) out of frame

11) 9^2 = 9*9 = 81

12) 4^2 = 4*4 = 16

13) 12^2 = 12*12 = 144

14) 6^2 = 6*6 = 36

15) 10^2 = 10*10 = 100

16) 5^2 = 5*5 = 25

17) 3^3 = 3*3*3 = 27

18) 10^3 = 10*10*10 = 1000

MrMuchimi3 years ago

6 0

Answer:

You multiply the number by itself a specified number of times

Step-by-step explanation:

You might be interested in

PLEASE help!!!! Jackie runs and dances for a total of 55 minutes every day. She dances 25 minutes more than she runs. Part A: Wr

Andrew [12]

Part a:

x + y = 55

y = x + 25

part b:

jackie runs 15 minutes every day.

part c:

it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run

step-by-step explanation:

let's call and while jackie is dancing

let's call x while jackie is running

then we know that jackie runs and dances for a total of 55 minutes every day

this means that:

x + y = 55

we also know that jackie dances 25 minutes more than she runs.

this meant that:

y = x + 25

now we substitute the second equation in the first and solve for the variable x

x + x + 25 = 552x = 55-252x = 30x = 15

jackie runs 15 minutes every day.

now we find the value of the variable -y

15 + y = 55y = 55-15y = 40

note that it is not possible for jackie to spend 45 minutes a day dancing, since the time she spends dancing and running is 55 minutes, and we know that it takes 15 minutes to run

7 0

4 years ago

Read 2 more answers

A recipe requires 1/3 cup of milk for each 1/4 cup of water.How many cups of water are needed for each cup of milk?

d1i1m1o1n [39]

3/4
Work
1/4+1/4+1/4=3/4
1/3+1/3+1/3=3/3=1

7 0

3 years ago

Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin

sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

$\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x$