Answer:
x=-1 y=1 z=-.7?
Step-by-step explanation:
I'm going to assume the crust covered by the dosenot matter because the total surface area cannot be found without the depth of the pie.
So the surface are is the area of the top of the pie, the top of the pie is circular and is equal to 2

r²
The diameter is the sum of 2 radii, hence r=8
D=12
= 2r =12
r=8
With the raduis the area can be found
A= 2

r²
A=2

8²
A=2(64)

A=128

If the pie cost 10.99, the cost per inch can be found by dividing the area by cost
cost/inch =128

/10.99
cost/inch =11.64

= 11.64(3.14)
= 36.57
The pie costs 36 cents per square inch
Answer:
180 cm^3
Step-by-step explanation:
A=lw
A=20×9
A=180
Answer:
351.658 square in
Step-by-step explanation:
First find the circumference of the circle
C = 25.13
Find area of the circle
A = 50.27
Multiply the circumference by the height
25.13 × 10 = 251.3
Add 251.3 with 50.27 twice
251.13 + 50.27 + 50.27 ≈ 351.658
Therefore your answer is D) 351.658 square in
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225