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lisov135 [29]
1 year ago
10

A bank features a savings account that has an annual percentage rate of 4.8 % with interest compounded monthly. Umbrosia deposit

s $6,500 into the account.
How much money will Umbrosia have in the account in 1 year?
What is the annual percentage yield (APY) for the savings account?
Mathematics
1 answer:
Scilla [17]1 year ago
5 0

S(8)=3500(1+(.047/4))^32

S(8)=$5086.40 in the account after 8 years.

a)The relative growth rate is .25, or 25%

b)at t=0, the population is 955e^.25(0)=955

c)at t=5; the population is 955*e^.25(5)=955*3.49=3333.28 bacterium.

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Which fraction has a terminating decimal as its decimal expansion?
ArbitrLikvidat [17]

Answer:

fraction which has a terminating decimal as its decimal expansion is:

1/5

Step-by-step explanation:

We are given 4 fractions:

1/3 , 1/5 , 1/7 and 1/9

We have to find which fraction has terminating decimal.

1/3 = 0.33333...

1/5 = 0.2

1/7 = 0.142857142857...

1/9 =0.11111.....

Hence, fraction which has a terminating decimal as its decimal expansion is:

1/5

3 0
3 years ago
Read 2 more answers
Name.<br> Solve using <br> Substitution <br> L<br> y = 3x + 2<br> 6x - 2y = 8
masya89 [10]

Answer:

No solution

Step-by-step explanation:

There is no solution to the system of equations y=3x+2 and 6x-2y=8, meaning that they are parallel to each other on a graph, with no points ever intersecting on each other's lines.

6 0
3 years ago
Find the value of X.
ch4aika [34]

Answer:

x= 60

Step-by-step explanation:

if y is the other missing side

y^2 = 64^2 + 48^2

y^2 = 4,096 + 2,304

y^2 = 6,400

100^2 = x^2 +y^2

x^2 = 10,000 - 6,400

x^2 = 3,600

x = 60

6 0
3 years ago
What is the solution of this equation x + 6 =24
lawyer [7]
If you are looking for x then it is X = 18
3 0
3 years ago
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An amusement park would like to determine if they want to add in a new roller coaster. In order to decide whether or not they sh
Rzqust [24]

Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given by:

n = 600, \pi = \frac{400}{600} = 0.6667

Hence, the bounds of the interval are given by:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 - 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6350

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6667 + 1.645\sqrt{\frac{0.6667(0.3333)}{600}} = 0.6984

The 90% confidence interval is given by: (0.6350, 0.6984).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

5 0
2 years ago
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