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Lostsunrise [7]
2 years ago
12

Can someone help me with this ASAP?

Mathematics
2 answers:
masya89 [10]2 years ago
7 0
Use the equation
7848 = 1548 + 300(t)
6300 = 300t
t = 21
1940 + 21 = 1961
It would be C
Maslowich2 years ago
5 0

Answer:It's A I think if not try B

Step-by-step explanation:

You might be interested in
Find The Quotient of 5/6÷ (-13/7)<br> 5/6÷(-13/7)=5/6. ​
Neko [114]

Answer:

  • - 35/78

Step-by-step explanation:

<u>The quotient of </u>

  • 5/6÷ (-13/7) =
  • 5/6×(-7/13) =
  • - 35/78
8 0
3 years ago
I GIVE BRAINLIEST! LOOK AT THE IMAGE BELOW.
MissTica
Answer: 8

Area of a triangle=(1/2)bh
16=(1/2)4x
16=2x
x=8
3 0
3 years ago
The number of violent crimes committed in a day possesses a distribution with a mean of 2.2 crimes per day and a standard deviat
VARVARA [1.3K]

Answer:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

Step-by-step explanation:

For this case we have the following info given:

\mu = 2.2 represent the mean

\sigma = 6 represent the deviation

We select a sample size of n=100. This sample is >30 so then we can use the central limit theorem. And we want to find the distribution for the sample mean and we know that the distribution is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And replacing we got:

\mu_{\bar X}= 2.2

\sigma_{\bar X}= \frac{6}{\sqrt{100}}= 0.6

6 0
3 years ago
Without plotting the point (-5, 10), determine in which quadrant
sashaice [31]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
3 years ago
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